Check Your QUANT concepts - 1

ALLIGATION METHOD

1. In what ratio should freely available water be mixed with the wine worth  Rs. 60 per litre so that after selling the mixture at Rs. 50 per litre , the profit will be 25% ?
a. 1:2
b. 2:3
c. 3:4
d. 4:5

2. Avinash covered 150 km distance in 10 hours. The first part of his journey he covered by Car, then he hired a Rickshaw. The speed of the car and rickshaw is 20 kmph and 12 kmph respectively. The ratio of the distances covered by the car and the rickshaw is
a. 2:3
b. 4:5
c. 1:1
d. None of these

3. Modern electronic shop sold the 30% hardware at the profit of 50% and 90% software at the profit of 10%. The average profit percent of the Modern electronics shop is, if it sells only these two kinds of items:
a. 15
b. 20
c. 25
d. 45

4. A milkman has two types of milk. In the first container the percentage of milk is  80% and in the second container the percentage of the milk is 60%. If he mixes 28 litres of milk of the first container to the 32 litres of the second container , then the percentage of the milk in the mixture is :
a. 63.99
b. 69.33
c. 72.5
d. 75.2

5. The average weight of boys in a class is 30 kg and the average weight of girls in the same class is 20 kg. If the average weight of the whole class is 23.25 kg, what could be  the possible strength of boys and girls respectively in the same class ?
a. 14 and 26
b. 13 and 27
c. 17 and 27
d. None of these

# Above questions can be solved by other methods also, but try these questions by alligation method only, to sharpen your concept...!!

# Answers 
1. 
water ------------------ wine
0--------------------------60
-------------40-------------
20------------------------40

1:2

2. 
The average speed of Avinash is 150/10 -->> 15 kmph

12------------------------20
--------------15------------
5--------------------------3

5:3 (ratio of the time taken by the rickshaw and car)

So, the ratio of distances covered by rickshaw to car is 
5*12 : 3*20 -->> 60:60 -->> 1:1

3.
10------------------------50
--------------x--------------
90------------------------30

The actual ratio is 3:1
So, the reversed ratio is 1:3

Now, divide the difference of 10 and 50 in the ratio 1:3, then add the first part to the 10 or subtract the second part from the 50.
Required average -->> 10 + (50-10)*1/4
-->> 10+10 = 20
or 50 - (50-10)*3/4 = 20

4.
60-------------------------80
---------------x--------------
32-------------------------28

8:7

reversed ratio: 7:8

(80-60)*7/7+8 = 20*7/15 = 9.33

Thus, the required percentage = 60+9.33 = 69.33

5.
20---------------------------30
--------------23.25-----------
6.75------------------------3.25

27:13


Number of boys to girls = 13:27